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Solution: a. In increasing food production from 0 to 2 million units, production of clothing decreases from 16,000 to 15,000 units. Thus, the opportunity cost of producing the rst 2 million units of food is 1 thousand units of clothing. The opportunity cost of a second and third additional 2 million units is 2,000 and 3,000 units of clothing, respectively. b. The opportunity cost of increasing food production is increasing from 1,000 units of clothing to 2,000 to 3,000 units of clothing. c. Increasing clothing and food costs are re ected in a concave (outward-sloping) production-possibility frontier. Moving down the frontier from point A to points B, C, D, E, and F shows that to produce 2 million incremental units of food (the 2-million-unit-length horizontal dashed lines in Figure 1-4), we must give up more and more units of clothing (the vertical dashed lines of increasing length). Solved Problem 1.5 Explain how division of labor and specialization enhance production in an advanced society. Solution: Through the division of labor and specialization, the population within a given geographic region, instead of being self-suf cient and producing the full range of goods and services wanted, can concentrate its energies and time in the production of only a few goods and services in which its ef ciency is greatest. Thus, specialization and division of labor allow greater output. By then exchanging some of the goods and services so produced for different goods and services produced similarly within a different geographic region, the regions populations as a whole end up consuming a larger number and greater diversity of goods and services than would otherwise be the case.

Details from the NASA Bulletins (see Fig. 2.6 and App. C) Columns 3 7 19 20 21 32 Description Satellite number: 25338 Epoch year (last two digits of the year): 00 Epoch day (day and fractional day of the year): 223.79688452 (this is discussed further in Sec. 2.9.2) First time derivative of the mean motion (rev/day2): 0.00000307 Inclination (degrees): 98.6328 Right ascension of the ascending node (degrees): 251.5324 Eccentricity (leading decimal point assumed): 0011501 Argument of perigee (degrees): 113.5534 Mean anomaly (degrees): 246.6853 Mean motion (rev/day): 14.23304826 Revolution number at epoch (rev): 11,663

1 2 2 2 2 2 2 2

34 43 9 16 18 25 27 33 35 42 44 51 53 63 64 68

n2 0

Note Lightweight polylines don t store Z-axis or elevation information with each vertex point. Instead, the

2.7 Apogee and Perigee Heights Although not specified as orbital elements, the apogee height and perigee height are often required. As shown in App. B, the length of the radius vectors at apogee and perigee can be obtained from the geometry of the ellipse: ra rp a(1 a(1 e) e) (2.5) (2.6)

In order to find the apogee and perigee heights, the radius of the earth must be subtracted from the radii lengths, as shown in the following example.

2

specifically that the uplink is being considered. Thus Eq. (12.38) becomes c C d N0 U [EIRP]U c G d T U [LOSSES]U [k] (12.39)

In Eq. (12.39) the values to be used are the earth station EIRP, the satellite receiver feeder losses, and satellite receiver G/T. The free-space loss and other losses which are frequency-dependent are calculated for the uplink frequency. The resulting carrier-to-noise density ratio given by Eq. (12.39) is that which appears at the satellite receiver. In some situations, the flux density appearing at the satellite receive antenna is specified rather than the earth-station EIRP, and Eq. (12.39) is modified as explained next.

As explained in Sec. 7.7.3, the traveling-wave tube amplifier (TWTA) in a satellite transponder exhibits power output saturation, as shown in Fig. 7.21. The flux density required at the receiving antenna to produce saturation of the TWTA is termed the saturation flux density. The saturation flux density is a specified quantity in link budget calculations, and knowing it, one can calculate the required EIRP at the earth station. To show this, consider again Eq. (12.6) which gives the flux density in terms of EIRP, repeated here for convenience:

In decibel notation this is [

Polyline object has an Elevation property that specifies the Z elevation relative to the coordinate system

[EIRP]

In This :

1 4 r2

(12.40)

(12.41)

Substituting this in Eq. (12.40) gives [

[EIRP]

To assign a bulge factor to the polyline segments, use the SetBulge method. The following example sets the bulge on a Polyline segment: Public Sub TestAddBulge() Dim objEnt As AcadPolyline Dim dblVertices(17) As Double '' setup initial points dblVertices(0) = 0: dblVertices(1) = 0: dblVertices(2) = 0 dblVertices(3) = 10: dblVertices(4) = 0: dblVertices(5) = 0 dblVertices(6) = 7: dblVertices(7) = 10: dblVertices(8) = 0 dblVertices(9) = 5: dblVertices(10) = 7: dblVertices(11) = 0 dblVertices(12) = 6: dblVertices(13) = 2: dblVertices(14) = 0 dblVertices(15) = 0: dblVertices(16) = 4: dblVertices(17) = 0 '' draw the entity If ThisDrawing.ActiveSpace = acModelSpace Then Set objEnt = ThisDrawing.ModelSpace.AddPolyline(dblVertices) Else Set objEnt = ThisDrawing.PaperSpace.AddPolyline(dblVertices) End If objEnt.Type = acSimplePoly 'add bulge to the fourth segment objEnt.SetBulge 3, 0.5 objEnt.Update End Sub

[FSL]

Demand Supply Equilibrium Price and Quantity Government and Price Determination Elasticity True or False Questions Solved Problems Demand

(12.42)